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9x^2+16x^-2-40=0
We add all the numbers together, and all the variables
9x^2+16x-42=0
a = 9; b = 16; c = -42;
Δ = b2-4ac
Δ = 162-4·9·(-42)
Δ = 1768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1768}=\sqrt{4*442}=\sqrt{4}*\sqrt{442}=2\sqrt{442}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{442}}{2*9}=\frac{-16-2\sqrt{442}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{442}}{2*9}=\frac{-16+2\sqrt{442}}{18} $
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